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GXYCTF2019 luck_guy

链接:https://pan.baidu.com/s/1hoU9 uQsSeGr-6p7RBSm56w
提取码:ed2z

0x01 查看有无加壳

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没有加壳,64位文件

0x02 打开IDA64,查看main函数,F5反编译

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0x03 进入patch_me函数,接着进入get_flag函数界面

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0x04 进行代码分析 😞

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__int64 get_flag()
{
unsigned int v0; // eax@1
signed int i; // [sp+4h] [bp-3Ch]@1
signed int j; // [sp+8h] [bp-38h]@7
__int64 s; // [sp+10h] [bp-30h]@3
char v5; // [sp+18h] [bp-28h]@6
__int64 v6; // [sp+38h] [bp-8h]@1

v6 = *MK_FP(__FS__, 40LL);
v0 = time(0LL); //得到时间
srand(v0); //使用时间作为种子生成随机数字
for ( i = 0; i <= 4; ++i )
{
switch ( rand() % 200 ) // 产生1-199之间的随机数
{
case 1:
puts("OK, it's flag:");
memset(&s, 0, 0x28uLL);
strcat((char *)&s, f1); // f1='GXY{do_not_'
strcat((char *)&s, &f2); //f2初始为空
printf("%s", &s);
break;
case 2:
printf("Solar not like you");
break;
case 3:
printf("Solar want a girlfriend");
break;
case 4:
v5 = 0;
s = 9180147350284624745LL; //在IDA里面选中9180147350284624745LL按H键转换16进制为0x69,0x63,0x75,0x67,0x60,0x6f,0x66,0x7f
strcat(&f2, (const char *)&s); //f2和s拼接
break;
case 5:
for ( j = 0; j <= 7; ++j )
{
if ( ((((unsigned int)((unsigned __int64)j >> 32) >> 31) + (_BYTE)j) & 1)
- ((unsigned int)((unsigned __int64)j >> 32) >> 31) == 1 )
*(&f2 + j) -= 2;
else
--*(&f2 + j);
}
break;
default:
puts("emmm,you can't find flag 23333");
break;
}
}
return *MK_FP(__FS__, 40LL) ^ v6;
}

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分析可知flag是由f1f2组成,f1已经告诉,现在只需要求f2就行。

  • case4给f2赋值

  • case5对f2进行处理

swich函数需要排序和,因此顺序是: case5>case4>case1

0x05 脚本构建 🍔

由于IDA是反编译C语言,s=0x69,0x63,0x75,0x67,0x60,0x6f,0x66,0x7f应该逆序成s = 0x7F666F6067756369LL作为小端储存,关于大小端推荐师傅的**文章**

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flag = 'GXY{do_not_'
f2 = [0x7F, 0x66, 0x6F, 0x60, 0x67, 0x75, 0x63, 0x69][::-1]
s = ''
for i in range(8):
if i % 2 == 1:
s = chr(int(f2[i]) - 2)
else:
s = chr(int(f2[i]) - 1)
flag += s
print(flag)

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1
GXY{do_not_hate_me}

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